Cisco Adaptive Security Appliance Software and Firepower Threat Defense Software DNS Inspection Denial of Service Vulnerability
<p>A vulnerability in the DNS inspection handler of Cisco Adaptive Security Appliance (ASA) Software and Firepower Threat Defense (FTD) Software could allow an unauthenticated, remote attacker to cause a denial of service condition (DoS) on an affected device.</p>
<p>This vulnerability is due to a lack of proper processing of incoming requests. An attacker could exploit this vulnerability by sending crafted DNS requests at a high rate to an affected device. A successful exploit could allow the attacker to cause the device to stop responding, resulting in a DoS condition. </p>
<p>Cisco has released software updates that address this vulnerability. There are no workarounds that address this vulnerability.</p>
<p>This advisory is available at the following link:<br><a href="https://tools.cisco.com/security/center/content/CiscoSecurityAdvisory/cisco-sa-asaftd-dos-nJVAwOeq" target="_blank" rel="noopener">https://tools.cisco.com/security/center/content/CiscoSecurityAdvisory/cisco-sa-asaftd-dos-nJVAwOeq</a></p>
<p>This advisory is part of the April 2022 release of the Cisco ASA, FTD, and FMC Security Advisory Bundled publication. For a complete list of the advisories and links to them, see <a href="https://tools.cisco.com/security/center/viewErp.x?alertId=ERP-74836">Cisco Event Response: April 2022 Cisco ASA, FMC, and FTD Software Security Advisory Bundled Publication</a>.</p>
Security Impact Rating: High
CVE: CVE-2022-20760
Source: Cisco Adaptive Security Appliance Software and Firepower Threat Defense Software DNS Inspection Denial of Service Vulnerability (https://tools.cisco.com/security/center/content/CiscoSecurityAdvisory/cisco-sa-asaftd-dos-nJVAwOeq?vs_f=Cisco%20Security%20Advisory&vs_cat=Security%20Intelligence&vs_type=RSS&vs_p=Cisco%20Adaptive%20Security%20Appliance%20Software%20and%20Firepower%20Threat%20Defense%20Software%20DNS%20Inspection%20Denial%20of%20Service%20Vulnerability&vs_k=1)